private void btnOpen_Click(object sender, System.EventArgs e)
{
OpenFileDialog opnFileBoxImage = new OpenFileDialog();
if (opnFileBoxImage.ShowDialog() == DialogResult.OK)
{
strBLOBFilePath = opnFileBoxImage.FileName;
pictureBox1.Image = Image.FromFile(strBLOBFilePath);
}
}
==================================================
(Save Image file in to SQL server)
note :- ( create table imageTable (empid int, img image))
private void button1_Click(object sender, System.EventArgs e)
{
MemoryStream ms = new MemoryStream();
PictureBox1.Image.Save(ms, PictureBox1.Image.RawFormat);
byte[] bytes = ms.GetBuffer;
SqlConnection con = new SqlConnection("server=SERVERNAME;database=DATABASENAME;user id=SA; password=");
con.Open();
SqlCommand cmd = new SqlCommand();
cmd.Connection = con;
cmd.CommandText = "insert imagetable values(@img)";
cmd.Parameters.Add(new SqlParameter("@img", SqlDbType.Image)).Value = bytes; cmd.ExecuteNonQuery();
con.Close();}
=========================================
(retreive image from SQL server)
(button click)
sqlconnection con = new sqlconnection(connectionPath); sqlcommand cmd1 = new sqlcommand("Select img from imageTable", con);
sqldataadapter da = new sqldataadapter(cmd1);
dataset ds = new dataset(); da.fill(ds, "ima");
byte[] bytes = ((Bytes)(ds.tables(0).rows(0)(0)));
memortstream ms = new memortstream(bytes);
picturebox1.image = picturebox1.image.fromstream(ms);
picturebox1.refresh();
Friday, January 4, 2008
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